Okay, so lessee...first need acceleration (body hitting the water). I think that makes Fw=(m)(a) into...wait a minute. The 65 kg is either the mass or the weight, it can't be both. I think we're missing either a formula or a variable. *squints*
...except if Fw = Fn = 9.8m/s(2), then never mind. That'd make the formula into 9.8m/s2=(65)(a). Then you divide the 9.8 by 65, and what you have left is A, acceleration. Which I...guess is maybe the velocity too. I don't remember terms too well. XD
So Fnet = (65)(whatever A is), though I'm not sure how the "2m below the surface" plays into it.
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timeasmymeasure
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Date: 2006-01-09 12:11 am (UTC)Actually, that looks more like the nightmare that was high school Physics. D: Does your book not have the formula for net force and whatever else?
no subject
Date: 2006-01-09 02:16 am (UTC)no subject
Date: 2006-01-09 02:51 am (UTC)no subject
Date: 2006-01-09 03:53 am (UTC)Fw=(m)(a)
Fw=Fn Fn=9.80m/s(2)
m=mass
a=accelleration
w=weight
n=...I have no idea.
And none of them make sense in context of the problem!
*hugs you for helping*
no subject
Date: 2006-01-09 04:02 am (UTC)...except if Fw = Fn = 9.8m/s(2), then never mind. That'd make the formula into 9.8m/s2=(65)(a). Then you divide the 9.8 by 65, and what you have left is A, acceleration. Which I...guess is maybe the velocity too. I don't remember terms too well. XD
So Fnet = (65)(whatever A is), though I'm not sure how the "2m below the surface" plays into it.
I think.
no subject
Date: 2006-01-09 04:07 am (UTC)*huggles*
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Date: 2006-01-09 07:28 am (UTC)no subject
Date: 2006-01-09 04:15 am (UTC)no subject
Date: 2006-01-09 04:19 am (UTC)no subject
Date: 2006-01-09 04:48 am (UTC)no subject
Date: 2006-01-09 04:35 pm (UTC)*explodes*